Question

6.
I
In the sequence 1, 4, 8, 10, 16, 21, 25, 30 and 43, the number of blocks of consecutive terms
whose sums are divisible by 11 is
A) only one
B) exactly two
exactly three
D) exactly four​

Answer 1

Answer:

exact 3

25,30

4,8,10

8,10,16,21

Answer 2

Answer:

Exactly 3 set of numbers are available whose sums are divisible by 11.

Given:

In the sequence 1, 4, 8, 10, 16, 21, 25, 30 and 43,  

To find:

The number of blocks of consecutive terms whose sums are divisible by 11.

Solution:  

The sequence 1, 4, 8, 10, 16, 21, 25, 30 and 43,  

The consecutive terms whose sum is divisible by 11 are

(i) 25, 30 = 55

(ii) 4, 8, 10 = 22

(iii) 8, 10, 16, 21 = 55

            Exactly three set of consecutive terms are available whose sums are divisible by 11.