Question

6. If A and B are acute angles such that
tan A = 1/2, tan B =1/3 and
tan (A + B) =tanA+tanB/1-tanAtanB
, find A+B.​

Answer 1

Step-by-step explanation:

We know ,

tan (A+B)=(tan A+ tan B)/(1-tanAtanB)

=(1/2+1/3)/(1-1/2×1/3)

=(5/6)/(1-1/6)

=(5/6)/(5/6)

=1

Since tan 45 degrees is 1.

Hence A+B is 45 degrees or pi/4.

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Answer 2

Answer:

Tan A = 1/2

Tan B = 1/3

Tan ( A+B ) = Tan A + Tan B / 1 - Tan A. Tan B

= 1/2 + 1/3 / 1-1/2.1/3

= 3+2/6 / 5/6

= 1

Tan (A+B ). = 45 degree