Question

6. If an array b[11][8] is stored as column wise and b[2][2] is stored at 1024 and b[3][3] at 1084. Find out the base address, size of an element and address of b[5][3].

Answer 1

Answer:

964

Step-by-step explanation:

Address of b[1][1] = 964

Explanation:

For B[2][2], B = ?

I = 2

J = 2

R₀ = 0

C₀=0

Number of rows(M)=11

Address of element Arr[I][J]=B+W[(I-R₀)+(J-C₀)]

So, Address of element B[2][2]= B+W[(2-0)+11(2-0)]

or, 1024=B+W[2+11(2)]

1024=B+W[2+22]

1024=B+W[24]

1024=B+24W. -(i)

And,

1084=B+W[(3-0)+11(3-0)]

1084=B+W[3+11(3)]

1084=B+W[3+33]

1084=B+W[36]

1084=B+36W. -(ii)

Now, on subtracting equation(i) from equation(ii), we get

1084=B+36W

1024=B+24W

- - -

 

60=12W

_____________

So, W

=60/12

therefore, W=5

So, B=1024-24W

B=1024-24(5)

=1024-120

=904

now ,b[1][1]= 904+5[(1-0)+11(1-0)]

=904+5[1+11]

=904+5[12]

=904+60

=964