Question

6. If log 2 = 0.3010, and log 3 = 0.4771 then log 150
(a) 2.1761
(c) 2.5762
(b) 2.8751
(d) 2.6126​

Answer 1

Answer:

$log(150) \\ = log(10 \times 3 \times 5) \\ = log(10 \times 3 \times \frac{10}{2} ) \\ = log(10) + log(3) + log(10) - log(2) \\ 1 + 0.4771 + 1 - 0.301 \\ 2.1761$