Question

6. If log (x+y/3) =1/2 (log x+ log y), then find the value of x/y + y/x
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Answer 1

Answer:

7

Step-by-step explanation:

log(x+y) - log3 = 1/2 [ log x + log y ]

2log(x+y) - 2log3 = logxy

2log(x+y) - logxy = 2log3

log(xsq. + ysq. + 2xy) - logxy = 2log3

log (xsq./xy +ysq./xy + 2xy/xy) = 2log3

log(x/y + y/x + 2) = 2log3

log(x/y +y/x +2) = log9

ANTILOG. in LHS & RHS

x/y + y/x +2 = 9

x/y + y/x = 7