Question

6. If m= -2 and n=2; find the value of :


(iii) 6m-3 + 4n2
(iv) 2n3 - 3m​

Answer 1

Step-by-step explanation:

1. 6m-3+4n2

6×(-2)-3+4×2×2

(-12)-3+16

(-12)+13

1

2. 2n3-3m

2×2×3-3×(-2)

12+(-6)

12-6

6

Answer 2

Answer:Given:

m = -2, n = 2

6m - 3 + 4n2

= 6(-2) - 3 + 4(2)2

= -12 - 3 + 16

= -15 + 16

= 1

2n3 - 3m

= 2(2)3 - 3(-2)

= 2*2*3 - (-6)

= 12 + 6

= 18

Hope that this answer helps you..