6 If the equation 2x² -6x + (k+3) = 0 has two equal roots then
the value of k is
(a) 9/8. (b). 3/2. (c). -3/4. (d). -1/8
Answers
Answered by
0
-3/4 is the correct answer
Answered by
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If there are 2 equal roots, then
D = b^2-4ac= 0
(-6)^2 - 4(2)(k+3) =0
36 - 8(k+3) =0
36 - 8k - 24 =0
Transposing 8k to the other side,
12 = 8k
8k =12
K = 12/8
Therefore , k=3/2
Therefore ,
Your answer is
(b) 3/2
D = b^2-4ac= 0
(-6)^2 - 4(2)(k+3) =0
36 - 8(k+3) =0
36 - 8k - 24 =0
Transposing 8k to the other side,
12 = 8k
8k =12
K = 12/8
Therefore , k=3/2
Therefore ,
Your answer is
(b) 3/2
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