Question

A bus increases its speed by 10%. After that, it again increases its speed by 20%. By what percentage is the bus's final speed greater than its original speed?

Answer 1

Explanation:

let the buses original speed be 100m/s

it increases its speed by 10% thus new speed is 110m/s

now it again increases by 20%.

(20/ 100)×110= 110/5 = 22. thus new speed is 110+22 = 132m/s

thus final speed of bus is 132m/s. original speed was 100m/a. thus increase on speed is 132-100=32m/s

% difference is (32/100)×100= 32%

thus final speed is 32% more than original speed

plz mark as brainliest

Answer 2

here is an awesome formula for doing such type of questions

For simultaneous increases in percentage x and y we use

Overall Percentage increase $=x+y+ \frac{x\times y}{100}$

So here overall percentage increase in the speed will be

             $10+20+\frac{10\times 20}{100}=32$

So the percent increase in car will be 32%

#SPJ2