Question

6. If the prime factorization of a natural number n is 2*3 x 3*2 x 5*2 x 7, write the number
of consecutive zeros in n.
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Answer 1

Refer to the picture

Answer 2

Step-by-step explanation:

There will be 3 consecutive zeroes in N.

Step-by-step explanation:

Given : If the prime factorization of a natural number N is

To find : Write the number of consecutive zeros in N?

Solution :

Prime factorization of a natural number N is

The consecutive zeros are the power of multiple of 2 and 5

So, There will be 3 consecutive zeroes in N