Question

6. In a box of 100 electric bulbs, 10 are defective. One bulb is taken out at random from the box
What is the probability that the bulb drawn is
(a) defective?
(b) non-defective?​

Answer 1

Answer:

Total outomes = 100

(a). Favourable outcomes= 10

therefore,

Probability of an event= favourable outcomes/ total outomes

P ( defective ) = 10/100 = 1/10

(b) favourable outcomes = 90

therefore,

P ( non defective ) = 90/100 = 9/10