Question

6. In a triangle ABC, D is a point on BC, such
that angle CAD = angle B.
Prove that : ZADC = ZBAC.​

Answer 1

Answer:

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Answer 2

Answer:

Hi mate ! Here is the answer of your question

Step-by-step explanation:

Given ∠CAD=∠B

Now, In △ABD,

∠B+∠BAD=∠ADC ...........(Exterior angle property)

∠CAD+∠BAD=∠ADC

∠BAC=∠ADC

Hence Proved.