Question

6.
In a Wheatstone's bridge three resistors P,Q,R connected in three arms and
fourth arm is formed by two resistors S, S, connected in parallel. The condition for the bridge to be balanced will be

Answer 1

Answer:

The balanced condition for Wheatstone bridge is  QP​=SR​

Here S=​S1​S2​​/S1​+S2  (as S1​ and S2​ are connected in parallel in S arm)

so, PQ​= R(S1+S2)/S1S2