Question

for any positive integer n prove than n³-n is divisible by 6 or show that the product of any 3 consecutive positive integer is always divisible by 6​

Answer 1

Step-by-step explanation:

(n – 1) , n, (n + 1) are consecutive integers thus as proved a must be divisible by 3. Thus, n³ – n is divisible by 6 for any positive integer n. Method 2: ... ∴ n = 3p or 3p + 1 or 3p + 2, where r is some integer.

Answer 2

Answer:

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