Question

6) In the circuit shown, solve and
Calculate. total resistance in the arm
CE, Total current drawn from the battery.Current in each arm i.e.,
AB and CE of the circuit​

Answer 1

Explanation:

Total resistanace in CE =6 ohms(4 and 2 are in series).

Total current=1 amps(total resistanace is 6 parallel 6 equivalent to 3 ohms so total current =3 volts/3 ohms=1 amps).

Both branches will have same current(0.5 amps) because of same resistance.