Question

6. In the given figure, ABCD is a rectangle in which AB =
40 cm and BC = 24 cm. If P, Q, R, S are midpoints of
AB,BC, CD and DA respectively, find the area of the shaded region.​

Answer 1

Answer:

Area of rectangle=l*b=40*25=1000cm2

p is the midpoint of AB

PB=1/2*40=20cm

q is the midpoint of BC

BQ=1/2*25=12.5cm

Area of triangle PBQ=1/2*b*h

Area of triangle PBQ=1/2*20*12.5

Area of triangle PBQ=10*12.5

Area of triangle PBQ=125cm2

All four triangles are equal

Area of 4 triangle =125*4

Area of 4triangle =500cm2

Area of shaded region =1000-500

Area of shaded region =500cm2

hope this will help

mark brainliest

Answer 2

Answer:

480 cm ²

step by step explanation :

join points PR AND SQ . these two lines bisect each other on point O

here AB = DC = SQ = 40 cm and AD = BC = RP = 24 cm

also OP = OR = RP / 2 = 24 / 2 = 12 cm

from the figure we observed that ,

area of triangle SPQ = area of triangle SRQ

hence , area of shaded region 2x (area of SPQ)

2 × ( ½ ( SQ × OP ) )

2 × ( ½ ( 40 cm × 12 cm ) )

2 × ( ½ ( 480 cm ) )

2 × 240

480 cm ²