Question

6. In the given figure, the chord AB of
the larger of the two concentric circles,
with centre O, touches the smaller
circle at C. Prove that AC = CB.
​

Answer 1

Explanation:

In the bigger circle=>

AB is chord...........(given)

for smaller circle =>

AB is tangent

so if we joint centre to AB it will be 90°

.......(tangent property)

OC is perpendicular to AB

as AB is tangent for small circle

Now,

we know perpendicular drawn from centre to chord bisects the chord!!

So if OC is perpendicular to AB

It will divide it in equal ratio

i. e => AC = AB

Answer 2

Answer:

since AB is tangent so ANGLEOCB=90

SO OC perpendicular on AB

AB is chord so OC bisects AB

AC=BC