Question

A stone is dropped from the top of a building of height h.
After 1 second another stone is dropped from the balcony
of a flat, 20 metres below the top. What is the height of
the building, if both the stones reach the bottom
simultaneously? (g = 10 m/s2)
(a) 312.5 m
(6) 31.25 m
(c) 75.5 m
(d) 125 m
Answer it with explanation ❤​

Answer 1

Answer:

31.25

Explanation:

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Answer 2

halo mate

Given,

Initial velocity, u = 0 (In both the cases)

Height of tower = h

Height of balcony = h − 20

When stone is dropped from the tower, suppose the time taken is t, then for the second

case it will be t − 1.

Thus using equation of motion,

h = ut + = 1/2gt raise to 2=0+ 1/2gt raise to 2------------------(i)

and h − 20 =1/2g(t-1)raise to 2--------------------------------------(ii)

Solving (i) and (ii), we get

t = 2. 5 s

and h = 31. 25

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