Chinese, asked by rushikeshr707, 8 months ago

6. In trapezium ABCD, (Figure 1.6
side AB || side DC, diagonals AC a
BD intersect in point O. If AB = 2
DC = 6, OB = 15 then find OD.
B
A
Fig. 1.60​

Answers

Answered by tanvireddy29
2

Answer:

OD=4.5

Explanation:

Given,

side AB|| side DC

AB=20

DC=6

OB=15

In ∆COD and ∆AOB

angel COD= angle AOB (vertically opposite angles

angle CBO= angle ABO (alternate angles, CD||BA and BD is transversal line)

By AA test of similarity

∆COD ~∆AOB

  • CD/AB=OD/OB

(corresponding sides are proportional)

  • 6/20=OD/15
  • OD= 4.5

Answered by arpitsingh5764
0

Answer:

This is not Chinese

Explanation:

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