Question

6. In trapezium ABCD, (Figure 1.6
side AB || side DC, diagonals AC a
BD intersect in point O. If AB = 2
DC = 6, OB = 15 then find OD.
B
A
Fig. 1.60​

Answer 1

Answer:

OD=4.5

Explanation:

Given,

side AB|| side DC

AB=20

DC=6

OB=15

In ∆COD and ∆AOB

angel COD= angle AOB (vertically opposite angles

angle CBO= angle ABO (alternate angles, CD||BA and BD is transversal line)

By AA test of similarity

∆COD ~∆AOB

• CD/AB=OD/OB

(corresponding sides are proportional)

• 6/20=OD/15
• OD= 4.5

Answer 2

Answer:

This is not Chinese

Explanation: