6. In trapezium ABCD, (Figure 1.6
side AB || side DC, diagonals AC a
BD intersect in point O. If AB = 2
DC = 6, OB = 15 then find OD.
B
A
Fig. 1.60
Answers
Answered by
2
Answer:
OD=4.5
Explanation:
Given,
side AB|| side DC
AB=20
DC=6
OB=15
In ∆COD and ∆AOB
angel COD= angle AOB (vertically opposite angles
angle CBO= angle ABO (alternate angles, CD||BA and BD is transversal line)
By AA test of similarity
∆COD ~∆AOB
- CD/AB=OD/OB
(corresponding sides are proportional)
- 6/20=OD/15
- OD= 4.5
Answered by
0
Answer:
This is not Chinese
Explanation:
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