Question

6 is the mean proportional between x and y and 48 is the third proportional to x and y. Find the values of x and y.

Answer 1

Answer:

mean proportional between x and y = 6

√xy=6

xy=36 y=36/x

now third proportional = y^2/x

48= {(36/x)^2}/x

48=36×36/x^2×1/x

48/(36×36) =1/x^3

8/216 = 1/x^3

x=6/2

x=3

now xy = 36

3×y= 36

y=12

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