Question

6. Length of the fence of a trapezium shaped field PQRS is 80 m. If PQ = 15 m, QR = 28 m, RS = 17 m, find the area
of this field. Side PQ is perpendicular to the parallel sides PS and QR.​

Answer 1

Answer:

360 m^2

Step-by-step explanation:

As PQ is perpendicular to the parallel sides PS and QR , it is clear that PQ = height of the trapezium = 15 m.

And PS = 80 - ( 15+17+28) = 80-60 = 20m.

Now, The lengths of the parallel sides PS and QR air respectively 20m and 28m.

So,

The area of the trapezium is = ½ × height × ( the sum of the two parallel sides)

or, ½ × 15 × (20+28)

or, ½ × 15 × 48

or, 15 × 24

or, 360

Therefore The area is 360 m^2.