6 litres of paint is needed to completely paint a
large cube. If the cube is broken into two equal
halves, then how much paint would now be
required to completely paint both the smaller
cubes ?
Answers
Step-by-step explanation:
answer is 7.559 litres
because if the original volume is l^3
the surface area is 6l^2
now if it is divided in half
volume is (L^3)/2
therefore the length of each side is now l/(3√2)
therefore total surface area of two cubes is 2×6(l/(3√2))^2
now if 6litres of paint is needed for 6l^2 surface area
6×(3√2)litres are needed for two cubes.
=7.559litres
Step-by-step explanation:
1 L = 1000m³
therefore volume of big cube is 1000m³
side of big cube is,
= √1000
= 10m
TSA of big cube is,
= 6a²
= 6 x 10²
= 600m²
When Cube is cut into two equal, it forms two equal cuboids with,
length = 5m
breadth = 10m
height = 10m
TSA of one cuboid is,
= 2(lb + bh + lh)
= 2(5 x 10 + 10 x 10 + 5 x 10)
= 2(50 + 100 + 50)
= 2 x 200
= 400m²
therefore, TSA of two cuboid are
2 x 400 = 800m²
if 600m² needs 6L of paint
then 800m² needs 8L of paint
