6 persons A, B, C, D, E and F r comparing their weights and each of them is having a different weight.
•D-heavier than only 2 persons
•E-only person heavier than F and lighter than D
•C- less than only B's weight
*3rd heaviest weight is 100 kgs
*5th heaviest weight is 60 kgs
Answers
Answer:
1) We have,
6 persons A,B,C,D,E and F who are comparing
their weights.
According to the question,
First,D is heavier than only two persons.
Donly 2 persons)
=>D is the 4th heaviest person out of 6.
2)
.
Second, E is the only person heavier than F and
lighter than D.
=D>E>F
=>E and Fare 5th and 6th heaviest person out
of 6.
3) Third,
C's weight is less than only B's weight.
->C<B(only)
=>C is 2nd heaviest person and B is 1st heaviest
person.
Overall order becomes,
=>B>C>A>D»E>F
Our required 2nd heaviest person is C.
More information: Weight of A is 100kg.
Weight of E is 60kg.
Answer:
Directions for questions. These questions are based on the following information. Six persons A, B, C, D, E and F are comparing their weights and each of them is having a different weight. D is heavier than only two persons. E is the only person heavier than F and lighter than D. C’s weight is less than only B’s weight. The third heaviest weight is 100kgs and the fifth heaviest weight is 60kgs.
Step-by-step explanation:
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