Question

6 pipes are required to fill a tank in 1 hour 2 minutes. How long will it take if only 5 pipes of the same type are used?

Answer 1

solutions :-

we have,

6 pipe are required to fill a tank in 1 hour 2 minutes.

Find the time to fill tank by one pipe :-

6 pipe = 62 minutes    [ 1 hour = 60 minutes ]

1 pipe = 62 × 6 = 372 minutes

Now,

Find the time to fill tank by 5 pipes :-

1 pipe = 372 minutes

5 pipes = 372/5 = 74.4 minutes

Hence,

74.4 minutes or 1 hour 14.4 minutes Will take if only 5 pipes of the same type are used.

Answer 2

$\huge \red {Hello \: Friends}$

$\underline \bold{Given}$

$\bf{6 \: pipes \: are \: required \: to \: fill \: a \: tank}$
$\bf{in \: 1 \: hour \: 2 \: minutes \: }$

$\underline \bold{To \: find}$

$\bf{5 \: pipes \: \: how \: much \: time\: will \: take}$

$\boxed{Answer \: = = > }$

$first \: find \: the \: time \: required$
$by \: a \: pipe \: to \: fill \: the \: tank$

$\bf{6 \: = 1 \: hour \: 2 \: mintues}$

$\blue{We \: know \: that}$

$\bf{1 \: hour \: = 60 \: mitutes}$

$\bf{6 = 62 \: minutes}$

$\bf{62\times 6}$

$\bf{372 \: minutes}$

$\orange{Therefore....}$

$\bf{1 \: pipe \: will \: take \: 372 \: mitues}$

$\boxed{1 \: pipe \: = 372 \: mitutes \: }$

$\pink{NOW \: ....}$

$\bf{5 \: pipes \: = 372}$

$\bf{ 5 \: pipes \: = \frac{372}{5} }$

$\bf{5 \: pipes \: = 74.4 \: mitues}$

$\boxed{5 \: pipes \: 74.4 \: mitues \: or \: 1 \: h \: 14.4 \: m}$

$\huge{Thanks}$

$\boxed{Be \: Brainly}$