Question

6 pipes are required to fill a tank in 1 hour 20 minutes how long will it take if only 5 types of the same type are used

Answer 1

Hey there! ☺☻☺

$Given,\\\text{6 pipe can fill a tank } = 60 + 20 = 80 \ min\\\text{5 pipes can fill a tank}= x \ min\\\\\because \text{It is in inverse proportion}\\6\times80 = 5\times x\\x = \frac{6\times80}{5} \\x = 96 \ min\\\\Hence,\text{Time taken by 5 pipe to fill tank} = \boxed{\boxed{\bold{96 \ min}}}$

Hope It Helps You! ☺☻☺

Answer 2

Heya

Number of pipes and time taken are inversely proportional.

That is, if number of pipes decrease then the time increases and vice versa.

Time taken by 6 pipes to fill the tank = 1hour 20min = 60+20=80min

Let the time taken by 5 pipes by y

As they are inversely proportional,

6×80=5×y

6×80/5 = y

96min= y

Time taken by 5 pipes to fill the tank= 1hour and 36minutes

Hope it helps^_^