Question

6 pipes are required to fill a tank in 1 hour 20 minutes. How long will it take if only 5 pipes of the same type are used?

Answer 1

solutions :-

we have,

6 pipe are required to fill a tank in 1 hour 20 minutes.

Find the time to fill tank by one pipe :-

6 pipe = 80 minutes    [ 1 hour = 60 minutes ]

1 pipe = 80 × 6 = 480 minutes

Now,

Find the time to fill tank by 5 pipes :-

1 pipe = 480 minutes

5 pipes = 480/5 = 96 minutes

Hence,

96 minutes or 1 hour 36 minutes Will take if only 5 pipes of the same type are used.

Answer 2

Jio ${\mathcal {\huge {Hey}}}$

${\mathbb {\huge {Answer}}}$

${\bold{\boxed {Given :}}}$

6 pipes are required to fill a tank in 1 hour 20 minutes.

To Find️ ➡️➡️➡️

The time to fill tank with 5 pipes

$\huge \bold {Main \: Solution}$

1 hr 20 min = 80 min

➡️ 1 pipe = 80 × 6 = 480 min

▶️Now,

➡️ 1 pipe = 480 min
➡️ 5 pipe = 480 / 5 = 96 min

⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️↙️↙️↙️↙️↙️↙️↙️↙️↙️↙️↙️↙️↙️↙️↙️↙️↙️
Hence, 96 minutes will it take for 5 pipes.

➡️ ➡️ ➡️ ➡️ ➡️ ➡️ OR ↙️↙️↙️↙️↙️↙️↙️↙️↙️↙️↙️↙️↙️

1 Hour 36 minutes will needed for 5 pipes

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