6 pipes are required to fill a tank in 1hr 20minutes how long will it take if only 5 pipes of the same type are used
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Answer:
Step-by-step explanation:
Let the desired time to fill the tank be x minutes.
In 80 mins a tank is filled by 6 pipes
Lesser the number of pipes more will be the time required by it to fill the tank.
So, this is a case of inverse proportion.
Hence, 80×6=x×5
⇒
5
80×6
=x
⇒x=96
Thus, the time is taken to fill the tank by 5 pipes is 96 minutes or 1 hour 36 minutes.
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