Question

6. Prove that the perimeter of a square is less than that of an
equivalent parallelogram on the same base.
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Answer 1

Answer:

Let PQCB be a square and ABCD be a parallelogram (please have a close look at the figure). If you look at the figure you can see that AB and CD hypotenuses which are certainly greater in length than PB and QC. So the perimeter of square PQCB is less than that of parallelogram ABCD on same base. Hence proved.