Question

6. Q. An element A has atomic number (11) and an element B has atomic number (17).
(iii) Nature of A and B
(iv) Formula existing between A and B
(v) Formula of sulphate of A
(vi) Bonding existing between A and B​

Answer 1

Answer:

• A is metallic in nature. B is non-metallic in nature.
• AB (NaCl)
• A2SO4 (Na2SO4)
• Ionic bond / Electrovalent bond.

Answer 2

Given:

Element 'A', Atomic no.=11

Element 'B', Atomic no.=17

So, electronic configuration of 'A':

K(2), L(8), M(1)

Valency=+1

electronic configuratiom of 'B':

K(2), L(8), M(7)

Valency=–1

Solution:

(iii) Element 'A' is metallic and is an alkali metal in its Nature. It is sodium.

(iv) Element A and B combine to form compound, AB,

i.e., NaCl(Sodium Chloride)

(v) The formula of the sulphate of Element 'A' is A₂SO₄

i.e., Na₂SO₄ (Sodium Sulphate)

(vi) Element 'A' and 'B' combine to form an ionic compound, which involves transfer of electrons.