(√6) raised to power x-2=1
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(root 6)^(x - 2) = 1
=> (root 6)^(x-2) = (root 6)^0
=> x - 2 = 0
=> x = 2.
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mannat44:
aapka ye question wrong hai kyuki x-2=0 so, x=0+2=2 hota hai
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