Question

6. Salil wants to put a picture in a frame. The picture is 7*3/5 cm wide.​

Answer 1

$\large{\underline{\rm{\green{\bf{Correct \: Question:-}}}}}$

Salil wants to put a picture in a frame. The picture is $\sf 7\dfrac{3}{4} \: cm$ wide. To fit the frame in the picture cannot be more than $\sf 7 \dfrac{3}{10} \: cm$ wide. How much should be the picture be trimmed?

$\large{\underline{\rm{\green{\bf{Given:-}}}}}$

Width of the picture =  $\sf 7\dfrac{3}{4} \: cm = \dfrac{38}{5} \: cm$

Width of the frame = $\sf 7 \dfrac{3}{10} \: cm=\dfrac{73}{10} \: cm$

$\large{\underline{\rm{\green{\bf{To \: Find:-}}}}}$

Length of the picture that should be trimmed.

$\large{\underline{\rm{\green{\bf{Solution:-}}}}}$

Given that,

Width of the picture =  $\sf 7\dfrac{3}{4} \: cm = \dfrac{38}{5} \: cm$

Width of the frame = $\sf 7 \dfrac{3}{10} \: cm=\dfrac{73}{10} \: cm$

∴ The picture should be trimmed by = $\sf \bigg[ \bigg(\dfrac{38}{5}- \dfrac{73}{10} \bigg) \bigg]$

The LCM of 5, 10 = 10

So, LCM = 10

Now, change each of the given fraction into an equivalent fraction having 10 as the denominator.

$\sf = \bigg[ \bigg( \dfrac{38}{5} \times \dfrac{2}{2} \bigg) \bigg] - \bigg[ \bigg( \dfrac{73}{10} \times \dfrac{1}{1} \bigg) \bigg]$

$\sf = \bigg( \dfrac{76}{10} \bigg) - \bigg( \dfrac{73}{10} \bigg)$

$\sf = \dfrac{(76-73)}{10}$

$\sf = \underline{\underline{\dfrac{3}{10} \: cm}}$

Thus, the picture should be trimmed by (3/10) cm

Answer 2

Answer:

3/10

Step-by-step explanation:

Width of the picture is 7³/4cm

cm 38/4

cm 38/4Width of the frame is 7³/10 cm

cm 38/4Width of the frame is 7³/10 cm 73/10

The picture should be trimmed by [38 - 73

5 10

LCM of 5 and 10 is 10

SO, 70 - 73

10 10

70-73 = 3

10 10 cm.

ANSWER IS 3

10 CM.

HOPE IT'S HELPFUL ☺️