Question

| 6. सर्वसामेकाओं का प्रयोग कर गुणनफल ज्ञात कीजिए
| 0 111 102 (ii) 105 x 97 ।
(0 001982 (vi) (0.98)​

Answer 1

Step-by-step explanation:

(ii) 105 * 97

(100+5)*(100-3)

(x+a)(x-b) = x² + (a-b)x - ab

(100+5)(100-3)

= (100)² + (5-3)100 - 5*3

= 10,000 + 200 - 15

= 10,185

Answer 2

Answer:

i) 11,322

ii) 10,185

Step-by-step explanation:

i)111×102=111×(100+2) distribution property of multiplication over addition

=111×100+111×2

=11100+22

=11,322

ii)105×97

distribution property of multiplication over subtraction

ii)105(100-3)=105×100-105×3

=10500-315

=10,185