Question

6. Show that the points A(1,2), B(3,6), C(5,10) and D(3,2) are the vertices of a parallelogram.​

Answer 1

Answer:

the distance between the point

A(1,2)and B(3,6)=√(1-3)²+(2-6)²

=√(-2)²+(-4)²

=√4+16

=√20 =2√5

do rest of your own BC,CD and AC

and get the answer