Question

6. Simplify: please​

Answer 1

Answer:

The value is $\frac{1}{2x^{2}}-2$.

Step-by-step explanation:

Simplify the expression as follows:

$(2x-\frac{1}{2x})^{2}-(2x+\frac{1}{2x})(2x-\frac{1}{2x})=[(2x)^{2}+(\frac{1}{2x})^{2}-2.2x.\frac{1}{2x}]-[(2x)^{2}-(\frac{1}{2x})^{2})]$

                                                   $=4x^{2}+\frac{1}{4x^{2}}-2-4x^{2}+\frac{1}{4x^{2}}$

                                                   $=\frac{2}{4x^{2}}-2$

                                                   $=\frac{1}{2x^{2}}-2$

Thus, the value is $\frac{1}{2x^{2}}-2$.