Question

6) Solve: 99x + 101y = 499; 101x + 99y = 501
$5 \times 6325325$
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Answer 1

Given that 99x + 101y = 499 … (1)

101x + 99y = 501 … (2)

Adding equations (1) and (2), we get.

200x + 200y = 1000 Or, x + y = 5 … (3)

Subtracting (1) from (2), we get,

2x – 2y = 2 Or, x – y = 1 … (4)

Adding (3) and (4), we get,

2x = 6 x = 3

Putting the value of x in (3),

we get, y = 2

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Answer 2

Answer:

x=2 ; y=3

Step-by-step explanation:

Given 99x + 101y = 499 _______(1)

101x + 99y = 501 ____________(2)

Adding equation 1 and 2

200x + 200y = 1000

(divide both sides by 200)

we get ;

x +y =5 _______(3)

subtracting equation (2) from (1)

2x - 2y = 2

( divide both sides by 2)

-× - y =-1 _________(4)

ADDING EQUATION 3 AND 4

X + Y = 5

X - Y= -1

+__________

2x = 4

x = 4/2

x= 2

put x=2 in equation (3)

x+y= 5

2+y=5

y=5-2

y=3