Question

6. t² (t - 3)² – (t- 3)²
Factorise it​

Answer 1

t²(t-3)²–(t-3)²

using identity (a²-b²)=a²+2ab+b²

t²(t-3)²– (t-3)²

t²(t²+6t-9) –(t²+6t-9)

t⁴+6t³-9t²-t²-6t+9

Answer 2

Answer:

This is the correct answer Hope it will help you