Question

6
$6x {}^{2} - 3 - 7x$
​

Answer 1

Answer:

6x

2

−3−7x=6x

2

−7x−3=0

⇒6x

2

+2x−9x−3=0

⇒2x(3x+1)−3(3x+1)=0

⇒(2x−3)(3x+1)=0

Zeros =

2

3

,

3

−1

α+β=

a

−b

⇒

2

3

−

3

1

=

6

7

=

6

(−7)

=

a

−b

αβ=

a

c

⇒(

2

3

)(

3

−1

)=

2

−1

=

6

−3

=

a

c

Hence proved.

Step-by-step explanation:

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Answer 2

Answer:

6x

2

−3−7x=6x

2

−7x−3=0

⇒6x

2

+2x−9x−3=0

⇒2x(3x+1)−3(3x+1)=0

⇒(2x−3)(3x+1)=0

Zeros =

2

3

,

3

−1

α+β=

a

−b

⇒

2

3

−

3

1

=

6

7

=

6

(−7)

=

a

−b

αβ=

a

c

⇒(

2

3

)(

3

−1

)=

2

−1

=

6

−3

=

a

c

Hence proved.

Step-by-step explanation:

#Hope you have satisfied with this answer.