Question

6. The current of 1.0 A is flowing in the conductor. What
is the number of electrons flowing per second in the
conductor?
(2012)​

Answer 1

Explanation:

ANSWER

Given,

e=1.6×10

−19

C, I=4.8 A

Let number of electrons per second be n.

The current is defined as rate of flow of charge,

I=

t

q

Hence

q=n×e

Therefore, I=

t

n×e

Substituting values,

4.8 =n×1.6×10

−19

Hence, n=

1.6×10

−19

4.8

=3×10

19

electrons per second.