Question

6. The equation of the line passing through the point (5, –4) with slope –7/2 is

Answer 1

$\huge\boxed {Answer}$

We know that

Equation of the line

y - y1 = dy/dx (x - x1)

y - (-4) = (-7/2) (x - 5)

y + 4 = (-7/2) (x - 5)

2(y + 4) = -7 (x - 5)

2y + 8 = -7x + 35

7x + 2y - 27 = 0

Answer 2

Answer:

Here is your answer

Step-by-step explanation:

y - y1 = dy/dx (x - x1)

y - (-4) = (-7/2) (x - 5)

y + 4 = (-7/2) (x - 5)

2(y + 4) = -7 (x - 5)

2y + 8 = -7x + 35

7x + 2y - 27 = 0