Question

6. The mid value of a class interval is 32. If the class size is 10 find the upper and lower limits of the class​

Answer 1

Answer:

27-37

Step-by-step explanation:

let the upper and lower limit be x and y

x - y = 10

x + y = 2(32)

x - y + x + y = 10 + 64 = 74

2x = 74

x = 37

y = x - 10 = 37 - 10 - 27

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