Question

6. The product of coefficient of terms in - 4 a2b + 14 bc2 +5ca2

Answer 1

Answer:

Step-by-step explanation:

Let a=((1+2x+3x  

2

)  

6

+(1−4x  

2

)  

6

)

∴ Coefficient of x  

2

 in the expansion of the product (2−x)  

2

((1+2x+3x  

2

)  

6

+(1−4x  

2

)  

6

)

   =2( Coefficient of x  

2

 in a)−1(Constant of expansion)

In the expansion of ((1+2x+3x  

2

)  

6

+(1−4x  

2

)  

6

),  

Constant =1+1=2

Coefficient of x  

2

= Coefficient of x  

2

 in (  

6

C  

0

​  

(1+2x)  

6

(3x  

2

)  

0

)+ Coefficient of x  

2

 in (  

6

C  

1

​  

(1+2x)  

5

3)−  

6

C  

1

​  

(4)

=  

6

C  

2

​  

4+6×3−24

=6=+18−24=54

Then, coefficient of x  

2

 in (2−x)  

2

((1+2x+3x  

2

)  

6

+(1−4x  

2

)  

6

)

=2×54−1(2)=108−2=106

Answer 2

The answer is a³b²c³..

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