Question

6. The relative density of an object is 3 and it
has a mass of 600 g. What is the volume of
water it will displace if it is immersed in the
water? [Ans.: 200 mL]​

Answer 1

Given :

• Relative density of object = 3
• Mass of object = 600 g

To find :

• Volume of water displaced

Solution :

$\boxed{\sf Relative \: density = \: \dfrac{Density \: of \: object}{Density \: of \: water }}$

$\tt3 = \dfrac{Density \: of \: object }{1 \: g {cm}^{ - 3} }$

$\underline{\therefore\sf The \:density \: of \: object = 3g {cm}^{ - 3} }$

Mass of the object = 600 g

$\boxed{ \tt \: Density \: = \frac{mass}{volume} }$

$\tt \implies 3 = \dfrac{600}{volume}$

$\implies \tt \: volume = \dfrac{600}{3} = 200 {cm}^{3}$

Volume of water displaced = Volume of the object

= 200 cm³

= 200 mL

$\boxed{ \sf \therefore The \:volume \: of \: water \: displaced \: is \: 200 \: m L . }$

Answer 2

Answer:

Given:

• The relative density of an object is 3 and it has a mass of 600 g.

Find:

• What is the volume of water it will displace if it is immersed in the water?

Using formula:

• Relative density = Density of object/Density of water.

• Density = Mass/Volume.

Calculations:

=> 3 = Object density/1 gcm-³

=> 3 gcm-³ ------- Eq (1)

=> 3 = 600/Volume.

=> 600/3

=> 200 cm³ -------- Eq (2)

Volume of water is equal to Volume of object:

=> 200 cm³ = 200 ml

Required answer = 200 ml.