Question

6) The sides of a triangle ABC are AB, BC, AC whose equations are respectively y-2=0 ; y =3x-7 and 2y+x =0. Find the coordinates of points A , B and CJio​

Answer 1

Step-by-step explanation:

5) -2y + 19z- 77 = 0 Check sum = -60. Eliminate y by multiplying (5) by 27/2 and subtracting from (4). We find. 653 1959. (6) -- z + -- = 0 Check sum = +653. 2. 2 which gives z = 3.

Answer 2

A(-4,2) B ( 3,2) C(2,-1)

Equation of AB : y-2 = 0 ....... 1

Equation of BC : y=3x-7 ........ 2

Equation pf AC = 2y+x = 0 ...... 3

On solving 1 and 2 we get the coordinates of B

from eq. (1) y = 2  

put the value of y in eq. 2 we get

2= 3x-7

9=3x

x= 3  coordinates of B (3,2)

on solving eq. 2 and 3 we get the coordinates of C

y = 3x-7 put the value of y in eq. 3

2(3x-7) +x = 0

6x-14 +x = 0

7x=14

x= 2

from eq. 2 we get y = 3(2)-7 = 6-7 = -1

Coordinates of C are (2,-1)

0n solving eq. 1 and 3 we get the coordinates of A

from eq 1 y = 2

put y = 2 in eq. 3 we get

2(2)+x = 0

4+x =0

x=-4

Coordinates of A are (-4,2)