Question

6.The sum of a two digit number is 9.If the tens digit is half of the ones digit , find the two digit number.


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Answer 1

Answer:

${\boxed{\bold\green{Two\:digit\:number = 36 }}}$

Step-by-step explanation:

Given:-

• Sum of a two digit number = 9
• Tens digit = 1/2 of one's digit.
• Two digit number = ?

Let the one's digit number be X. So ten's digit number = X/2

${\underline{\underline{\bold{According\:to\:question:-}}}}$

$\implies\sf X + \dfrac{X}{2} = 9$

$\implies\sf \dfrac{2X+X}{2} = 9$

$\implies\sf 3x = 9\times 2$

$\implies\sf 3x = 18$

$\tt *Diving\:both\:terms\:by\:3 \: :-$

$\implies{\boxed{\sf{X \: \: = \: \: 6}}}$

$\therefore\bold{One's\:digit = 6 }$

$\rule{300}{1}$

$\implies\sf Ten's\:digit = \dfrac{X}{2}$

$\implies\sf Ten's\:digit =\cancel{\dfrac{6}{2}}$

$\implies{\boxed{\bold {Ten's\:digit = 3}}}$

$\tt *Substituting\:values\: :-$

$\therefore\bold{Two\:digit\:number}$=${\boxed{\bold\green{36}}}$

Answer 2

Answer:

• The two digit number =36

Given :

• The sum of two digit number = 9

• The tens digit is half of the ones digit.

To find :

• The two digit number =?

Step-by-step explanation:

Let first number be x.

And, second number = x/2 because it is half of the first number.

The sum of both number = 9

∴ x + x/2 = 9

⟹ 2x + x/ 2 = 9

⟹ 3x/2 = 9

⟹ 3x = 9 × 2

⟹ x = 9 × 2/3

⟹ x = 6

Hence, One's digit = x = 6

Tens digit = x/2 = 6/2 = 3

So, The two digit number = 36