Question

6. The sum of digits of a 2-digit number is 11. If the number obtained by reversing the
digits is 9 less than the original number, find the number.
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Answer 1

Step-by-step explanation:

ones place be x

tens place no. be 11 - x

original no . 10(11-x ) + x

= 110 - 10x + x

= 110 - 9x

new no = 10 (x ) + 11 - x

= 10x + 11 - x

= 9x + 11

A/q

=> original no = new no

=> 110 - 9x = 9x + 11 + 9

=> - 18 x = 20 - 110

=> x = -90/-18

=> x = 5

hence, original no be 65

... new no be 56