6. The ten’s digit of a two-digit number exceeds it’s unit’s digit by 5. When digits are reversed, the
new number added to the original number becomes 99. Find the original number.
Answers
Answered by
1
Answer:
72
Step-by-step explanation:
[10(x+5) +x]+ [10x + (x+5)] = 99
10x+50+x+10x+x+5 = 99
22x+55 = 99
22x+55 = 99
22x= 44
x=2
original number = 10(2+5) +2
= 72
Answered by
0
Answer:
3/2
Step-by-step explanation:
Let x be the once digit
Then 10x is ten's digit
1st case:
=10x*5 + x
=50x + x
=51x
2nd case when number is reversed
=x*5 + 10x
=5x + 10x
=15x
So by adding 1st case and 2nd case we get 99
=> 51x + 15x = 99
=> 66x = 99
=> x = 99/66
=> x = 3/2 (divided by 33)....
Bye....
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