Question

6. Thedrug tolbutamine (FW = 270 g/mol) has a molar absorptivity of 703 M-1cm-1at a wavelength of 262 nm (which is in the UV region of the EMR spectrum). One tablet of this drug is dissolved in H2O and diluted to a volume of 2.00 L. If the solution exhibitsan absorbance of 0.687 in a 1.00 cm cell, how many grams of tolbutamine are contained in the tablet? C = A/b = 0.687/(703 M-1cm-1)(1.00 cm) = 9.77 x 10-4mol tolbutamine/L(9.77 x 10-4mol tolb./L)(2.00 L)(270 g tolb./mol tolb.) = 0.528 g

Answer 1

Answer:

The drug tolbutamine (FW = 270 g/mol) has a molar absorptivity of 703 M-1 cm-1 at a wavelength of 262 nm (which is in ...