Question

Two cars, parked at two points 300 km from each other on a straight highway, start moving
towards each other. After 3 hours, the distance between the cars is 30 km. Find the speed of
each car if the difference between their speeds is 10 km/h.

Answer 1

||✪✪ QUESTION ✪✪||

Two cars, parked at two points 300 km from each other on a straight highway, start moving towards each other. After 3 hours, the distance between the cars is 30 km. Find the speed of each car if the difference between their speeds is 10 km/h.

|| ✰✰ ANSWER ✰✰ ||

Lets assume That, Speed of both cars are x km/h and y km/h. (where x > y).

Than,

→ x - y = 10 ------------- Equation (1)

Now, Given That , Total distance b/w two points is 300km, and after 3 hours distance b/w them is 30km .

That Means , we can say That, They Cover Rest 270km b/w them in 3 hours.

So,

→ 3x + 3y = 270 km

→ 3(x + y) = 270

→ (x + y) = 90 ----------------- Equation (2)

Adding Both Equation we get,

→ (x - y) + (x+y) = 10 + 90

→ 2x = 100

→ x = 50km/h.

Putting in Equation (1) now,

→ 50 - y = 10

→ y = 50-10

→ y = 40 km/h.

Hence, Speed of both cars is 50km/h and 40km/h.

Answer 2

$\huge {\orange{ \underline{ \overline \: {\boxed{ \sf{QUESTION}}}}}}$

Two cars, parked at two points 300 km from each other on a straight highway, start moving towards each other. After 3 hours, the distance between the cars is 30 km. Find the speed of each car if the difference between their speeds is 10 km/h.

$\huge {\orange{ \underline{ \overline \: {\boxed{ \sf{ANSWER \: :}}}}}}$

• Let the Cars be A and B.
• Let the Cars be A and B.Let the Speed of Car A be 'x' and that of Car B be 'y', where x < y.
• Let the Cars be A and B.Let the Speed of Car A be 'x' and that of Car B be 'y', where x < y.Also the difference in their speed was 10 km/h.

Now According to the Question,

=> x - y = 10

=> y = x - 10 ----->(1)

The inital distance between the Cars was 300km. And after moving for 3 hrs toward each other, the distance between them was 30km.

Therefore distance travelled,

= (300 - 30) km

= 270 km.

Now, We have

Avg.Speed = Total Distance / Total time

Avg. Speed = 270/ 3

Avg.Speed = 90km/ hr.

Therefore, the Average Speed of both the car is 90km/ hr.

_____________________________________

Now,

=> x + y = 90

=> x + (x - 10) = 90 ____ from (1)

=> 2x - 10 = 90

=> 2x = 100

=> x = 50.

Thus the speed of the Car A = 50 km/ h and the Speed of Car B = 50 - 10 = 40 km/ h.