Question

6. There are two bags, one containing 4 red and 5, blue balls and the other containing 6 black and
2 white balls. One ball from each bag is taken out. What is the probability that the balls are
(i) red and black - (ii) blue and white
(iii), red and white
(iv) blue and black.
(HOTS]
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Answer 1

Answer:

(i) 10/17

(ii) 7/17

(iii) 6/17

(iv) 11/17

Step-by-step explanation:

Total Outcome in the First Bag= 4 red balls+ 5 blue balls= 9 balls

Total Outcome in the Second Bag= 6 black balls+ 2 white balls= 8 balls

Total outcome in both Bags= 9+8= 17 balls

(i) Red and Black Balls= 4+6= 10 balls

                             P(E)= 10/17

(ii) Blue and White Balls= 5+2= 7 balls

                                P(E)= 7/17

(iii) Red and White Balls= 4+2= 6 balls

                                P(E)= 6/17

(iv) Blue and Black Balls= 5+6= 11 Balls

                                 P(E)= 11/17

Answer 2

Answer:

tk is so ye yr jd uewucy chp