Question

6.There is a defective die in which two dots instead of four are printed.In which die,the chance of getting'2' is more,in defective die or in a normal die?Give the reason​

Answer 1

Step-by-step explanation:

In a non defective or unbiased dice the Probability of getting a odd number or a even number is 1/2

The question suggests it is a six sided defective dice with the probability of getting a odd number is 2 times getting the probability of an even number.

Hence the numbers on the dice will be

odd odd odd

even even odd

In this case the Probability of getting the odd number is 4/6 = 2/3

Probability of getting the even number is = 2/6 = 1/3

which satisfies the condition "probability of getting a odd number is 2 times getting the probability of an even number"

Now the extra odd number could be 5 or any other odd number.

i.e

1 3 5

2 4 5

OR

1 3 5

2 4 3(or any other)

hence the probability of getting a 5 in a single throw is 2/6 or 1/6

[spoiler]2/6 + 1/6 = 3/6 = 1/2[/spoiler]

Answer 2

In case of tossing of a defective die, prob of getting an even and odd number is mutually exhaustive and exclusive.

So, Prob of even + Prob of odd = 1 ( Exhaustive)

Prob of even + 2 (Prob of even) = 1

3(Prob of even) = 1

Prob of even = 1/3

So, prob of odd = 2/3

Since there are 3 odd numbers {1,3,5} . Prob of getting 5 is 1/3

Hence, getting 5 ( odd ) in a single thro