Question

6. Three consecutive integers add up to 51.
7. The sum of three consecutive multiples of 8 is 888. Find the multiples,
much that when they are taken in increasi​

Answer 1

Explanation:

6. Let the 1st integer be x

2nd integer = x+1

3rd integer = x+1+1 =x+2

Sum is 51

By condition,

x+x+1x+1 = 51

x+x+x+1+2 = 51

3x+3 = 51

3x = 51-3

3x = 48

x = 48/3

x = 16

The three numbers are 16, (16+1)=17,(16+2)=18

7. Let 1st multiple be x

2nd multiple = x+8

3rd multiple = x+8+8 = x+16

Sum is 888

By condition,

x+x+8+x+16 = 888

x+x+x+8+16 = 888

3x+24 = 888

3x = 888-24

3x = 864

x = 864/3

x = 288

The three numbers are 288, (288+8)=296, (288+16)=304

Answer 2

Answer:

887

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